(x+3)(x-1)=x^2+5

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Solution for (x+3)(x-1)=x^2+5 equation:


Simplifying
(x + 3)(x + -1) = x2 + 5

Reorder the terms:
(3 + x)(x + -1) = x2 + 5

Reorder the terms:
(3 + x)(-1 + x) = x2 + 5

Multiply (3 + x) * (-1 + x)
(3(-1 + x) + x(-1 + x)) = x2 + 5
((-1 * 3 + x * 3) + x(-1 + x)) = x2 + 5
((-3 + 3x) + x(-1 + x)) = x2 + 5
(-3 + 3x + (-1 * x + x * x)) = x2 + 5
(-3 + 3x + (-1x + x2)) = x2 + 5

Combine like terms: 3x + -1x = 2x
(-3 + 2x + x2) = x2 + 5

Reorder the terms:
-3 + 2x + x2 = 5 + x2

Add '-1x2' to each side of the equation.
-3 + 2x + x2 + -1x2 = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-3 + 2x + 0 = 5 + x2 + -1x2
-3 + 2x = 5 + x2 + -1x2

Combine like terms: x2 + -1x2 = 0
-3 + 2x = 5 + 0
-3 + 2x = 5

Solving
-3 + 2x = 5

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 2x = 5 + 3

Combine like terms: -3 + 3 = 0
0 + 2x = 5 + 3
2x = 5 + 3

Combine like terms: 5 + 3 = 8
2x = 8

Divide each side by '2'.
x = 4

Simplifying
x = 4

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